Bellator Kenai
Shifter
Posts : 56
Join date : 2014-02-17
 | Subject: My Things - Noooo Touchy!  Mon Mar 02, 2015 8:15 pm | |
| For KenaiBear: POSTING TEMPLATE. Writing will go here. Please feel free to use this, if you want to. | |
|
Dominus Demetri
Admin
Posts : 172
Join date : 2013-05-19
Location : Wichita, Kansas
Character sheet
Rank: Dominus
| | Subject: Re: My Things - Noooo Touchy! Mon Mar 02, 2015 11:03 pm | |
| For Demetri: where my demons hide But with the beast inside  A constant force, acting on a particle of mass m, will produce a constant acceleration a. Let us choose the x-axis to be in the common direction of F and a. What is the work done by this force on the particle in causing a displacement x?
We have, for constant acceleration, the relations a = ( V - v ) / t and x = ½ ( V + v ) t. Here v is the particle's speed at t = 0 and V is its speed at time t. The the work done is W = F x = m a x = m ( ( V - v ) / t ) ( ½ ( V + v ) ) t = ½ m V² - ½ m v².
We call one-half the product of the mass of a body and the square of its speed the kinetic energy of the body. If we represent kinetic energy by the symbol K, then K = ½ m v². We may then state the above equation in this way:
The work done by the resultant force acting on a particle is equal to the change in the kinetic energy of the particle.
A constant force, acting on a particle of mass m, will produce a constant acceleration a. Let us choose the x-axis to be in the common direction of F and a. What is the work done by this force on the particle in causing a displacement x?
We have, for constant acceleration, the relations a = ( V - v ) / t and x = ½ ( V + v ) t. Here v is the particle's speed at t = 0 and V is its speed at time t. The the work done is W = F x = m a x = m ( ( V - v ) / t ) ( ½ ( V + v ) ) t = ½ m V² - ½ m v².
We call one-half the product of the mass of a body and the square of its speed the kinetic energy of the body. If we represent kinetic energy by the symbol K, then K = ½ m v². We may then state the above equation in this way:
The work done by the resultant force acting on a particle is equal to the change in the kinetic energy of the particle.
There’s nowhere we can hide | |
|
Dominus Demetri
Admin
Posts : 172
Join date : 2013-05-19
Location : Wichita, Kansas
Character sheet
Rank: Dominus
| | Subject: Re: My Things - Noooo Touchy! Tue Mar 03, 2015 12:25 am | |
| For my Favorite Werewolf:
CONTENT GOES HERE
T A G: --
M E N T I O N E D: --
N O T E S: -- |
| |
|
Sponsored content
| | Subject: Re: My Things - Noooo Touchy! | |
| |
|
